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11 exercise(s) shown, 0 hidden
BBy Bot
Jun 09'24
Show that if [math]X[/math] is a random variable with mean [math]\mu[/math] and variance [math]\sigma^2[/math], and if [math]X^* = (X - \mu)/\sigma[/math] is the standardized version of [math]X[/math], then
[[math]]
g_{X^*}(t) = e^{-\mu t/\sigma} g_X\left( \frac t\sigma \right)\ .
[[/math]]