The distribution of accidents for 84 randomly selected policies is as follows:
Number of Accidents | Number of Policies |
0 | 32 |
1 | 26 |
2 | 12 |
3 | 7 |
4 | 4 |
5 | 2 |
6 | 1 |
Total | 84 |
Determine which of the following models best represents these data.
- Negative binomial
- Discrete uniform
- Poisson
- Binomial
- Zero-modified Poisson
Prescription drug losses, S, are modeled assuming the number of claims has a geometric distribution with mean 4, and the amount of each prescription is 40.
Calculate [math]\operatorname{E}[(S-100)_{+}][/math]
- 60
- 82
- 92
- 114
- 146
X is a discrete random variable with a probability function that is a member of the (a,b,0) class of distributions. You are given:
- [math]\operatorname{P}(X = 0) = P(X = 1) = 0.25[/math]
- [math]\operatorname{P}(X=2) = 0.1875[/math]
Calculate [math]\operatorname{P}(X = 3) [/math]
- 0.120
- 0.125
- 0.130
- 0.135
- 0.140
A discrete probability distribution has the following properties:
- [math]p_k = c(1 + \frac{1}{k})p_{k+1} [/math] for [math]k = 1, 2, \ldots [/math]
- [math]p_0 = 0.5 [/math]
Calculate c.
- 0.06
- 0.13
- 0.29
- 0.35
- 0.40
A risk has a loss amount that has a Poisson distribution with mean 3. An insurance policy covers the risk with an ordinary deductible of 2. An alternative insurance policy replaces the deductible with coinsurance [math]\alpha[/math], which is the proportion of the loss paid by the policy, so that the expected cost remains the same.
Calculate [math]\alpha [/math].
- 0.22
- 0.27
- 0.32
- 0.37
- 0.42
The distribution of the number of claims, N, is a member of the (a, b, 0) class. You are given:
- [math]\operatorname{P}(N=k) = p_k[/math]
- [math]\frac{p_6}{p_4} = 0.5 [/math] and [math]\frac{p_5}{p_4} = 0.8[/math]
A zero-modified distribution, [math]N^M[/math], associated with [math]N[/math] has [math]\operatorname{P}(N^M = 0) = 0.1 [/math].
Calculate [math]\operatorname{E}(N^M) [/math].
- 3.64
- 3.73
- 3.85
- 4.00
- 4.05
You are given the following properties of the distribution of the annual number of claims, N:
- [math]\operatorname{P}(N=k) = p_k, \quad k = 0,1,2,\ldots[/math]
- [math]p_0 = 0.45 [/math]
- [math]\frac{p_n}{p_m} = \frac{m!}{n!} [/math] for [math]m \geq 1 [/math] and [math] n \geq 1 [/math]
Calculate the probability that at least two claims occur during a year.
- 0.16
- 0.18
- 0.21
- 0.23
- 0.26