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| revprev | Admin | Jun 27'24 at 3:14 | +8 | m | |
| revcur | Admin | (Created page with "'''Solution: A''' The probability that the digit 3 appears as a random digit is 1/10, and the number of digits equalling 3 among 10,000 random digits is approximately normally distributed with mean 10,000 * 1/10 = 1,000 and variance 10,000 * 0.1 * 0.9 = 900. Hence the probaility that we observe the digit 3 more than 931 times is approximately equal to the probability that a standard normal variable exceeds 31/30 and this is approximately equal to 0.1507.") | Jun 27'24 at 3:05 | +459 |