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| rev | Admin | (Created page with "'''Answer: B''' Per equivalence Principle: <math display="block"> \begin{aligned} G \ddot{a}_{35} & =100,000 A_{35}+0.4 G+150+0.1 G \ddot{a}_{35}+50 \ddot{a}_{35} \\ 1770 \ddot{a}_{35} & =100,000\left(1-d \ddot{a}_{35}\right)+0.4(1770)+150+0.1(1770) \ddot{a}_{35}+50 \ddot{a}_{35} \\ 1770 \ddot{a}_{35} & =100,000+708+150+\ddot{a}_{35}\left(177+50-100,000\left(\frac{0.035}{1.035}\right)\right) \end{aligned} </math> Solving for <math>\ddot{a}_{35}</math>, we have <ma...") | Jan 19'24 at 21:27 | +595 |