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| rev | Admin | (Created page with "'''Answer: C''' Let <math>C</math> be the annual contribution, then <math>C=\frac{{ }_{20} E_{45} \ddot{a}_{65}}{\ddot{a}_{45: 20}}</math> Let <math>K_{65}</math> be the curtate future lifetime of (65). The required probability is <math display="block"> \operatorname{Pr}\left(\frac{C \ddot{a}_{45: 20}}{{ }_{20} E_{45}}>\ddot{a}_{\overline{K_{65}+1}}\right)=\operatorname{Pr}\left(\frac{{ }_{20} E_{45} \ddot{a}_{65}}{\ddot{a}_{45: 20}} \frac{\ddot{a}_{45: 20}}{{ }_{20}...") | Jan 19'24 at 20:04 | +1,028 |