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| rev | Admin | (Created page with "'''Solution: D''' <math>1.07^n=4</math> so <math>n \ln (1.07)=\ln (4)</math> so <math>n=\ln (4) / \ln (1.07)=20.48954</math> years. '''References''' {{cite web |url=https://web2.uwindsor.ca/math/hlynka/392oldtests.html |last=Hlynka |first=Myron |website=web2.uwindsor.ca | title = University of Windsor Old Tests 62-392 Theory of Interest | access-date=November 23, 2023}}") | Nov 26'23 at 17:25 | +375 |