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revAdmin (Created page with "'''Solution: A''' <math display = "block"> \begin{align*} 1{\mathrm{00}}{\bigg(}1+{\frac{i}{2}}{\bigg)}^{22}\left[\left(1+{\frac{i}{2}}\right)^{2}-1\right]=2{\bigg(}1{\mathrm00}{\bigg)}{\bigg(}1+{\frac{i}{2}}{\bigg)}^{8}\left[{\bigg(}1+{\frac{i}{2}}{\bigg)}^{2}-1\right] \\ 2=(1+i)^{14}\\ i = (2^{1/14}-1)2 = 0.1015 = 10.15\%. \end{align*} </math> {{soacopyright | 2023 }}")Nov 17'23 at 22:53+376