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revAdmin (Created page with "'''Answer: D''' <math>\operatorname{EPV}(</math> Premiums <math>)=\operatorname{EPV}(</math> Benefits <math>)</math> <math>\mathrm{EPV}(</math> Premiums <math>)=3 P \bar{a}_{x}-2 P_{20} E_{x} \bar{a}_{x+20}</math> <math display="block"> \begin{aligned} & =3 P(1 / \mu+\delta)-2 P\left(e^{-20(\mu+\delta)}\right)(1 / \mu+\delta) \\ & =3 P(1 / 0.09)-2 P e^{-1.8}-1 / 0.09 \\ & =29.66 P \end{aligned} </math> <math>\operatorname{EPV}(</math> Benefits <math>)=1,000,000 \b...")Jan 19'24 at 21:23+905