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| rev | Admin | (Created page with "'''Solution: D''' The number of persons that show up for the flight equals <math>N</math> and has a binomial distribution with <math>n=100, p = 0.96 </math> and we are interested in the probability that <math>N \leq 98 </math>. This equals <math display = "block"> 1-P(N=99)-P(N=100) = 1- 100 \cdot 0.96^{99} \cdot 0.04 - 0.96^{100} = 0.9128. </math>") | Jun 26'24 at 1:56 | +352 |