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| rev | Admin | (Created page with "'''Answer: A''' <math>{ }_{1} V_{x}=A_{x+1}-P_{x} \ddot{a}_{x+1}=1-d \ddot{a}_{x+1}-P_{x} \ddot{a}_{x+1}</math> <math <math display="block"> =1-\underbrace{\left(P_{x}+d\right)} \ddot{a}_{x+1}=1-\ddot{a}_{x+1} / \ddot{a}_{x} </math> <math>\Rightarrow \ddot{a}_{x}\left(1-V_{x}\right)=\ddot{a}_{x+1}</math> Since <math>\ddot{a}_{x}=1+v p_{x} \ddot{a}_{x+1}</math> substituting we get <math>\ddot{a}_{x}\left(1-{ }_{1} V_{x}\right)=\frac{\ddot{a}_{x}-1}{v p_{x}} \Right...") | Jan 20'24 at 3:05 | +804 |