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| rev | Admin | (Created page with "'''Answer: B''' <math>A_{x: n \mid}^{1}={ }_{n} E_{x}</math> <math>A_{x}=A_{x: n}^{1}+{ }_{n} E_{x} A_{x+n}</math> <math>0.3=A_{x: n}^{1}+(0.35)(0.4) \Rightarrow A_{x: n}^{1}=0.16</math> <math>A_{x: n}=A_{x: n}^{1}+{ }_{n} E_{x}=0.16+0.35=0.51</math> <math>\ddot{a}_{x: n}=\frac{1-A_{x: n}}{d}=\frac{1-0.51}{(0.05 / 1.05)}=10.29</math> <math>a_{x: n}=\ddot{a}_{x: n}-1+{ }_{n} E_{x}=10.29-0.65=9.64</math> {{soacopyright|2024}}") | Jan 18'24 at 23:18 | +434 |