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| revprev | Admin | Jun 27'24 at 2:43 | 0 | m | |
| revcur | Admin | (Created page with "'''Solution: C''' By the central limit theorem, June's score is approximately normally distributed with mean 48*3/4 = 36 and variance 48 * 3/4 * 1/4 = 9. Therefore the probability that June passes the exam is approximately equal to the probability that a standard normal variable exceeds (30-36)/3 = -2. This is approximately equal to 0.9773.") | Jun 27'24 at 2:39 | +344 |