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| rev | Admin | (Created page with "'''Answer: D''' Under the Equivalence Principle <math>P \ddot{a}_{62: 101}=50,000\left(\ddot{a}_{62}-\ddot{a}_{62: 10}\right)+P\left((I A)_{62: 100}^{1}\right)</math> where <math>(I A)_{62: 10 \mid}^{1}=11 A_{62: 10 \mid}^{1}-\sum_{k=1}^{10} A_{62: k \mid}^{1}=11(0.091)-0.4891=0.5119</math> So <math>\quad P=\frac{50,000\left(\ddot{a}_{62}-\ddot{a}_{62: 10}\right)}{\ddot{a}_{62: 10 \mid}-(I A)_{62: 100}^{1}}=\frac{50,000(12.2758-7.4574)}{7.4574-0.5119}=34,687</math>...") | Jan 19'24 at 23:27 | +496 |