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revprevAdminJun 28'24 at 18:34+1m
revcurAdmin (Created page with "'''Solution: B''' The sum of the breaking strengths is approximately normally distributed with mean 100*10 = 1000 and variance 100. Hence the approximate probability that the rope will support a weight of 985 pounds is approximately the probability that a standard normal exceeds -15/10 = -1.5, which equals 0.0668.")Jun 27'24 at 20:32+316