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| rev | Admin | (Created page with "'''Answer: D''' <math display="block"> \begin{aligned} E(Z) & =\int_{0}^{\infty}{ }_{t} p_{x} \times \mu \times e^{0.05 \times t} e^{-\delta \times t} d t \\ & =\int_{0}^{\infty} e^{-0.03 \times t} \times 0.03 \times e^{0.05 \times t} e^{-0.06 \times t} d t \\ & =\frac{0.03}{0.04} \times\left. e^{-0.04 t}\right|_{0} ^{\infty}=0.75 \\ E\left(Z^{2}\right) & =\int_{0}^{\infty}{ }_{t} p_{x} \times \mu \times e^{0.05 \times 2 \times t} e^{-\delta \times 2 \times t} d t \\ &...") | Jan 18'24 at 12:45 | +798 |