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| revprev | Admin | Jul 4'24 at 22:04 | −17 | m | |
| revcurprev | Admin | Jun 26'24 at 15:57 | +4 | m | |
| revcur | Admin | (Created page with "'''Solution: A''' We have <math display = "block">P(T>6|T>3) = \frac{P(T>6)}{P(T>3)}</math>. However, <math>T</math> has a geometric distribution with <math>P(T=k) = (5/6)^{k-1}(1/6) </math> which means that <math display = "block"> \frac{P(T>6)}{P(T>3)} = \frac{\sum_{k\geq 7} (5/6)^{k-1}}{\sum_{k >4} (5/6)^{k-1}} = \frac{(5/6)^6}{(5/6)^3} = (5/6)^3 = 0.5787. </math>") | Jun 26'24 at 15:53 | +373 |