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rev | Admin | (Created page with "'''Answer: E''' In the final year: <math>\left({ }_{24} V+P\right)(1+\mathrm{i})=b_{25}\left(q_{68}\right)+1\left(p_{68}\right)</math> Since <math>b_{25}=1</math>, this reduces to <math>\left({ }_{24} V+P\right)(1+i)=1 \Rightarrow(0.6+P)(1.04)=1 \Rightarrow P=0.36154</math> Looking back to the <math>12^{\text {th }}</math> year: <math>\left({ }_{11} V+P\right)(1+i)=b_{12}\left(q_{55}\right)+{ }_{12} V\left(p_{55}\right)</math> <math>\Rightarrow(5.36154)(1.04)=14(0.15...") | Jan 20'24 at 3:01 | +551 |