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revAdmin (Created page with "'''Solution: C''' <math display="block"> \begin{align*} 77.1 &=\nu\Big(I a\Big)_{{\overline{n}|i}}^{}+\frac{n\nu^{n+1}}{i} \\ &=\nu\left[\frac{\ddot{a}_{\overline{{{n}}}}-n\nu^{n}}{i}\right]+\frac{n\nu^{n+1}}{i} \\ &=\frac{a_{\overline{n}|i}}{i}-\frac{n\nu^{n+1}}{i}+\frac{n\nu^{n+1}}{i} \\ &=\frac{a_{\overline{n}|i}}{i}=\frac{1-\nu^{n}}{i^{2}}=\frac{1-\nu^{n}}{0.01\ 1\vert025} \\ 0.85003 &=1-\nu^{n} \\ 1.105^{-n} &=0.14997 \\ n &= -\frac{\ln(0.14997)}{\ln(1.105)} = 19 \...")Nov 18'23 at 8:42+941