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| rev | Admin | (Created page with "'''Solution: B''' <math display="block"> 1200=1000 \exp \left(\int_0^4 \delta_r d r\right)=1000 \exp \left(\int_0^2 1.25 \delta d t+\int_2^4 \delta d t\right)=1000 \exp (2.5 \delta+2 \delta)=1000 \exp (4.5 \delta) </math> For the first year <math>1+i=e^{\int_0^1 1.25 \delta}=(1200 / 1000)^{1.25 / 4.5}</math> so <math>i=1.2^{1.25 / 4.5}-1=0.05195</math>. '''References''' {{cite web |url=https://web2.uwindsor.ca/math/hlynka/392oldtests.html |last=Hlynka |first=Myron...") | Nov 26'23 at 13:35 | +602 |