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| rev | Admin | (Created page with "'''Solution: B''' The two equations are: <math display = "block"> \begin{array}{l}{{P=(10,000r)a_{\overline{50}|0.04}+9,000(1.04)^{-5}=44,518.22r+7,397.34}}\\ {{1.2P=[10,000(r+0.01)]a_{\overline{50}|0.04}+11,000(1.04)^{-5}=44,518.22r+9,486.38}}\end{array} </math> Subtracting the first equation from the second gives 0.2P = 2089.04 for P = 10,445.20. Inserting this in the first equation gives r = (10,445.20 – 7,397.34)/44,518.22 = 0.0685. {{soacopyright | 2023 }}") | Nov 19'23 at 18:58 | +473 |