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| rev | Admin | (Created page with "'''Solution: C''' The number of defectives is approximately normal with mean 0.05 * 1900 = 95 and variance 90.25. Hence the probability of observing at least 115 defectives is approximately the probability that a standard normal exceeds (115-95)/9.5 = 2.105 which is approximately equal to 0.01765.") | Jun 27'24 at 17:59 | +300 |