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| rev | Admin | (Created page with "'''Solution: B''' The initial payment, X is <math display = "block"> \begin{aligned} 200,000 &=X\left({\frac{1}{1.03}}+{\frac{1.02}{1.03^{2}}}+\dots+{\frac{1.02^{19}}{1.03^{2}}}\right)=X{\frac{1/1.03-1.02^{20}\;/1.03^{21}}{1-1.02/1.03}}=17.7267 \\ X &= 11,282.42. \end{aligned} </math> The final payment is 11,282.42 (1.02)<sup>19</sup> =16, 436.36. {{soacopyright | 2023 }}") | Nov 18'23 at 12:08 | +379 |