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| rev | Admin | (Created page with "'''Solution: E''' The accumulation function is <math display = "block"> a(t)=\exp\biggl[\int_{0}^{t}(s^{2}/100)d s\biggr]=\exp(t^{3}/300). </math> The accumulated value of 100 at time 3 is <math>100 \exp(3^3 / 300) = 109.41743.</math> The amount of interest earned from time 3 to time 6 equals the accumulated value at time 6 minus the accumulated value at time 3. Thus <math display = "block"> \begin{array}{l}{{\left(109.41743+X\right)[a(6)/a(3)-1]=X}}\\ {{\left(109....") | Nov 17'23 at 22:07 | +620 |