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| rev | Admin | (Created page with "'''Solution: E''' The value at time 17 of the payments beginning at time 18 is <math display = "block"> 2500\left(\frac{1+k}{1.035}+\frac{\left(1+k\right)^{2}}{0.035^{2}}+\cdots\right)=2500\frac{\frac{1+k}{1.035}}{1-\frac{1+k}{1.035}}=2500\frac{1+k}{0.035-k} </math> The total present value is <math display = "block"> \begin{array}{c}{{1\,15,000=2500(1.035^{-2})a_{\overline{15}|0.035}+2500v^{17}\,\frac{1+k}{0.035-k}}}\\ {{46(0.035-k)=10.751\,6(0.035-k)+0.55720(1+k)}...") | Nov 18'23 at 12:06 | +588 |