Diff selection: Mark the radio buttons of the revisions to compare and hit enter or the button at the bottom.
Legend: (cur) = difference with latest revision, (prev) = difference with preceding revision, m = minor edit.
Legend: (cur) = difference with latest revision, (prev) = difference with preceding revision, m = minor edit.
| rev | Admin | (Created page with "'''Solution: B''' The number of heads is approximately normally distributed with mean 200 and variance 200 *1/2 * 1/2 = 50. Then the probability that the number of heads is between <math>200-x </math> and <math>200 + x </math> is the probability that a standard normal variable is between <math>\frac{-x}{\sqrt{50}}</math> and <math>\frac{x}{\sqrt{50}} </math>, which must equal 0.8. Since the 10<sup>th</sup> percentile of a standard normal variable is approximately equal...") | Jun 27'24 at 4:28 | +522 |