Diff selection: Mark the radio buttons of the revisions to compare and hit enter or the button at the bottom.
Legend: (cur) = difference with latest revision, (prev) = difference with preceding revision, m = minor edit.
Legend: (cur) = difference with latest revision, (prev) = difference with preceding revision, m = minor edit.
rev | Admin | (Created page with "'''Solution: A''' There are 10 payments at times <math>0,4,8, \ldots, 36</math>. Let <math>j</math> be the interest rate for a 4 year period and let <math>i</math> be the annual rate. Then <math>(1+j)=(1+i)^4</math>. Thus <math>100 \ddot{s}_{\overline{10} \mid j}=5(100) \ddot{s}_{\overline{5} \mid j}</math>. So <math display = "block">100 \frac{(1+j)^{10}-1}{j}(1+j)=5(100) \frac{(1+j)^5-1}{j}(1+j)</math>. Simplifying, using <math>(1+j)^{10}-1=\left((1+j)^5-1\right)\left...") | Nov 26'23 at 18:58 | +928 |