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| rev | Admin | (Created page with "'''Answer: D''' <math>\frac{V\left[{ }_{10} L\right]}{V\left[{ }_{11} L\right]}=\frac{\left(1+\frac{p}{d}\right)^{2}\left({ }^{2} A_{x+10}-A_{x+10}^{2}\right)}{\left(1+\frac{p}{d}\right)^{2}\left({ }^{2} A_{x+11}-A_{x+11}^{2}\right)}</math> <math>A_{x+10}=v q_{x+10}+v p_{x+10} A_{x+11}</math> <math>=(0.90703)^{1 / 2}(0.02067)+(0.90703)^{1 / 2}(1-0.02067)(0.52536)=0.50969</math> <math>{ }^{2} A_{x+10}=v^{2} q_{x+10}+v^{2} p_{x+10}{ }^{2} A_{x+11}</math> <math>=(0.9070...") | Jan 20'24 at 3:05 | +758 |