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| rev | Admin | (Created page with "'''Solution: A''' <math>108=K\left(1-v^{14}\right)</math> <math display="block"> 135=K\left(1-v^{28}\right)=K\left(1-v^{14}\right)\left(1+v^{14}\right)=108\left(1+v^{14}\right) \text { so } 1+v^{14}=135 / 108=1.25 \text { so } v^{14}=.25 \text {. } </math> Thus <math>K=108 /\left(1-v^{14}\right)=108 /(1-.25)=144</math>. Interest in 29th installment is <math>K\left(1-v^7\right)=144(1-\sqrt{.25})=72</math>. '''References''' {{cite web |url=https://web2.uwindsor.ca/ma...") | Nov 27'23 at 1:08 | +655 |