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| rev | Admin | (Created page with "'''Solution: E''' Let n = years. The equation to solve is <math display = "block"> \begin{array}{l}{{1000(1.03)^{2n}=2(1000)(1.0025)^{12n}}}\\ {{2n\ln1.03+\ln1000=12n\ln1.0025+\ln2000}}\\ {{m=23.775.}}\end{array} </math> This is 285.3 months. The next interest payment to Lucas is at a multiple of 6, which is 288 months. {{soacopyright | 2023 }}") | Nov 17'23 at 22:37 | +350 |