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| rev | Admin | (Created page with "'''Answer: D''' Let <math>P</math> be the premium per 1 of insurance. <math display="block"> \begin{aligned} & P \ddot{a}_{50: \overline{10}}=P(I A)_{50: 10}^{1}+{ }_{10} E_{50} A_{60} \\ & \ddot{a}_{50: 10 \mid}=\ddot{a}_{50}-{ }_{10} E_{50} \ddot{a}_{60}=17.0-0.60 \times 15.0=8 \\ & A_{60}=1-d \ddot{a}_{60}=1-\left(\frac{0.05}{1.05}\right) 15=0.285714 \\ & P\left(\ddot{a}_{50: \overline{10}}-(I A)_{50: 10}^{1}\right)={ }_{10} E_{50} A_{60} \\ & P=\frac{10}{\ddot{a}_...") | Jan 19'24 at 22:09 | +620 |