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| rev | Admin | (Created page with "'''Answer: A''' Let <math>P=0.00253</math> be the monthly net premium per 1 of insurance. <math <math display="block"> \begin{aligned} { }_{10} V & =100,000\left[\frac{i}{\delta} A_{55: 10 \mid}^{1}+A_{55: 10 \mid}-12 P \ddot{a}_{55: 10 \mid}^{(12)}\right] \\ & =100,000[1.02480(0.02471)+0.59342-(12)(0.00253)(7.8311)] \\ & \approx 38,100 \end{aligned} </math> Where <math <math display="block"> \begin{aligned} A_{55: \overline{10}}^{1} & =A_{55: \overline{10}}-{ }...") | Jan 20'24 at 2:56 | +808 |