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| rev | Admin | (Created page with "'''Solution: B''' <math>4 \frac{1-v^{2 n}}{i}=5 \frac{1-v^n}{i}</math> so <math>4 \frac{\left(1-v^n\right)\left(1+v^n\right)}{i}=5 \frac{1-v^n}{i}</math>. If <math>v^n=1</math> then <math>v=1</math> so <math>i=1</math> which cannot give <math>4 a_{\overline{2 n} \mid i}=5 a_{\bar{n} \mid i}</math>. Thus <math>4\left(1+v^n\right)=5</math> so <math>v^n=.25</math> so <math>(1+i)^n=4</math> so <math>(1+i)^{n / 2}=2</math> at which point money is doubled. Thus <math>n / 2</m...") | Nov 26'23 at 22:17 | +737 |