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| rev | Admin | (Created page with "'''Solution: D''' Fund A has value <math>(1.01)^m</math> after <math>m</math> months. Fund <math>\mathrm{B}</math> has value <math>e^{\int_0^t r / 6 d r}</math> after <math>t</math> years or <math>e^{\int_0^{m / 12} r / 6 d r}</math> after <math>m</math> months. Thus <math display="block"> 1.01^m=e^{r^2 /\left.12\right|_0 ^{m / 12}}=e^{m^2 / 12^3} \text { so } </math> <math>m \ln (1.01)=m^2 / 12^3</math> so <math>m=12^3 \ln (1.01)</math> months. Thus <math>T=m / 12=1...") | Nov 26'23 at 17:50 | +740 |