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| rev | Admin | (Created page with "'''Solution: D''' <math display = "block"> \overline{{{a}}}_{\overline{{{20}}|}}=1.5\overline{{{a}}}_{\overline{{{10}}|}},\;\;\;\frac{1-e^{-20\delta}}{\delta}=1.5\frac{1-e^{-10\delta}}{\delta},\;\;\;e^{-20\delta}-1.5e^{-10\delta}+0.5=0.</math> Let <math>X = e^{-10\delta}</math>. We then have the quadratic equation <math display = "block"> X^2 -1.5X + 0.5 = 0 </math> with solution <math>X = 0.5</math> for <math>\delta = \ln0.5\,/\,(-10)=0.069315. </math> Then, the a...") | Nov 18'23 at 10:46 | +671 |