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| rev | Admin | (Created page with "'''Solution: A''' <math>1000=(1 / 2) 1000(1.04)^7(1.04)^n</math> so <math>2=(1.04)^{7+n}</math> so <math>(7+n) \ln (1.04)=\ln 2</math> so <math>n=-7+\ln 2 / \ln (1.04)=</math> 10.673 years. '''References''' {{cite web |url=https://web2.uwindsor.ca/math/hlynka/392oldtests.html |last=Hlynka |first=Myron |website=web2.uwindsor.ca | title = University of Windsor Old Tests 62-392 Theory of Interest | access-date=November 23, 2023}}") | Nov 25'23 at 23:54 | +433 |