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| rev | Admin | (Created page with "'''Solution: C''' The interest earned is a decreasing annuity of 6, 5.4, etc. Combined with the annual deposits of 100, the accumulated value in fund Y is <math display = "block"> \begin{align*} &= 6(D s)_{\overline{{{10}}}|0.09}+100s_{\overline{{{10}}}|0.09}\\ &=6\left(\frac{10\left(1.09\right)^{10}-s_{\overline{{{10}}}|0.09}}{0.09}\right)+100\bigl(15.19293\bigr) \\ &= 565.38 + 1519.29 \\ &= 2084.67. \end{align*} </math> {{soacopyright | 2023 }}") | Nov 18'23 at 22:46 | +453 |