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revprev | Admin | Nov 26'23 at 13:19 | +9 | m | |
revcur | Admin | (Created page with "We want <math>\left(100(1+i)^2-50\right)(1+i)^n=200</math>. Thus <math>(1+i)^n=\frac{200}{\left(100(1+i)^2-50\right)}</math> so <math display="block"> n=\frac{\ln (200)-\ln \left(100(1+i)^2-50\right)}{\ln (1+i)} \text {. } </math> '''References''' {{cite web |url=https://web2.uwindsor.ca/math/hlynka/392oldtests.html |last=Hlynka |first=Myron |website=web2.uwindsor.ca | title = University of Windsor Old Tests 62-392 Theory of Interest | access-date=November 23, 2023}}") | Nov 26'23 at 0:03 | +475 |