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revprev | Admin | Jun 26'24 at 16:42 | +19 | m | |
revcur | Admin | (Created page with "The number of calls received after <math>t</math> seconds equals <math>N_t</math> has a Poisson distribution with mean <math>\lambda t </math> where <math>\lambda </math> is the expected number of calls after 1 second, namely 0.01. Hence the probability that we have at most one call during a 5 minute break equals approximately <math display = "block">1-\exp(-0.01 * 60*5) = 0.95</math>") | Jun 26'24 at 16:39 | +387 |