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| rev | Admin | (Created page with "'''Answer: A''' <math>P_{30: 20 \mid}=\frac{1}{\ddot{a}_{30: \overline{20}}}-d \Rightarrow \frac{2,143}{100,000}+0.05=\frac{1}{\ddot{a}_{30: \overline{20}}} \Rightarrow \ddot{a}_{30: 20}=14</math> <math>A_{30: \overline{20}}=1-d \ddot{a}_{30: \overline{20}}=1-0.05(14)=0.3</math> <math>G \ddot{a}_{30: \overline{20}}=100,000 A_{30: \overline{20}}+\left(200+50 \ddot{a}_{30: \overline{20}}\right)+\left(0.33 G+0.06 G \ddot{a}_{30: \overline{20}}\right)</math> <math>14 G=1...") | Jan 19'24 at 20:52 | +595 |