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| rev | Admin | (Created page with "'''Answer: B''' <math>\mathrm{EPV}(</math> premiums <math>)=\mathrm{EPV}(</math> benefits <math>)</math> <math>P\left(1+v p_{x}+v_{2}^{2} p_{x}\right)=P\left(v q_{x}+2 v^{2} p_{x} q_{x+1}\right)+10000\left(v^{3}{ }_{2} p_{x} q_{x+2}\right)</math> <math>P\left(1+\frac{0.9}{1.04}+\frac{0.9 \times 0.88}{1.04^{2}}\right)=P\left(\frac{0.1}{1.04}+\frac{2 \times 0.9 \times 0.12}{1.04^{2}}\right)+10000\left(\frac{0.9 \times 0.88 \times 0.15}{1.04^{3}}\right)</math> <math>2.5...") | Jan 19'24 at 21:05 | +548 |