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| rev | Admin | (Created page with "'''Answer: B''' By the equivalence principle, <math display="block"> 4500 \bar{a}_{x: \overline{20}}=100,000 \bar{A}_{x: \overline{20}}^{1}+R \bar{a}_{x: \overline{20}} </math> where <math display="block"> \begin{aligned} & \bar{A}_{x: 20 \mid}^{1}=\frac{\mu}{\mu+\delta}\left(1-e^{-20(\mu+\delta)}\right)=\frac{0.04}{0.12}\left(1-e^{-20(0.12)}\right)=0.3031 \\ & \bar{a}_{x: 20 \mid}=\frac{1-e^{-20(\mu+\delta)}}{\mu+\delta}=\frac{1-e^{-20(0.12)}}{0.12}=7.5774 \end{...") | Jan 19'24 at 21:38 | +640 |