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(Created page with "<div class="d-none"><math> \newcommand{\NA}{{\rm NA}} \newcommand{\mat}[1]{{\bf#1}} \newcommand{\exref}[1]{\ref{##1}} \newcommand{\secstoprocess}{\all} \newcommand{\NA}{{\rm NA}} \newcommand{\mathds}{\mathbb}</math></div> Assume that we are making raisin cookies. We put a box of 600 raisins into our dough mix, mix up the dough, then make from the dough 500 cookies. We then ask for the probability that a randomly chosen cookie will have 0, 1, 2, \dots\ raisins. C...")
 
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Assume that we are making raisin cookies.  We put a box of 600 raisins into our dough mix, mix up the dough, then make from the dough 500
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\newcommand{\exref}[1]{\ref{##1}}
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\newcommand{\mathds}{\mathbb}</math></div> Assume that we are making raisin cookies.  We put a box of
600 raisins into our dough mix, mix up the dough, then make from the dough 500
cookies.  We then ask for the probability that a randomly chosen cookie will have
cookies.  We then ask for the probability that a randomly chosen cookie will have
0, 1, 2, \dots\ raisins.  Consider the cookies as trials in an experiment, and let <math>X</math>
0, 1, 2, ... raisins.  Consider the cookies as trials in an experiment, and let <math>X</math>
be the random variable which gives the number of raisins in a given cookie.  Then we
be the random variable which gives the number of raisins in a given cookie.  Then we
can regard the number of raisins in a cookie as the result of <math>n = 600</math> independent
can regard the number of raisins in a cookie as the result of <math>n = 600</math> independent

Latest revision as of 01:09, 14 June 2024

Assume that we are making raisin cookies. We put a box of 600 raisins into our dough mix, mix up the dough, then make from the dough 500 cookies. We then ask for the probability that a randomly chosen cookie will have 0, 1, 2, ... raisins. Consider the cookies as trials in an experiment, and let [math]X[/math] be the random variable which gives the number of raisins in a given cookie. Then we can regard the number of raisins in a cookie as the result of [math]n = 600[/math] independent trials with probability [math]p = 1/500[/math] for success on each trial. Since [math]n[/math] is large and [math]p[/math] is small, we can use the Poisson approximation with [math]\lambda = 600(1/500) = 1.2[/math]. Determine the probability that a given cookie will have at least five raisins.