exercise:D5e8a1b25c: Difference between revisions

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(Created page with "<div class="d-none"><math> \newcommand{\NA}{{\rm NA}} \newcommand{\mat}[1]{{\bf#1}} \newcommand{\exref}[1]{\ref{##1}} \newcommand{\secstoprocess}{\all} \newcommand{\NA}{{\rm NA}} \newcommand{\mathds}{\mathbb}</math></div> For each of the densities in Exercise Exercise calculate the first and second moments, <math>\mu_1</math> and <math>\mu_2</math>, directly from their definition and verify that <math>g(0) = 1</math>, <math>g'(0) = \mu_1<...")
 
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<div class="d-none"><math>
For each of the densities in [[exercise:0e78fd06fb |Exercise]] calculate the first and second moments, <math>\mu_1</math> and <math>\mu_2</math>, directly from their definition and  
\newcommand{\NA}{{\rm NA}}
\newcommand{\mat}[1]{{\bf#1}}
\newcommand{\exref}[1]{\ref{##1}}
\newcommand{\secstoprocess}{\all}
\newcommand{\NA}{{\rm NA}}
\newcommand{\mathds}{\mathbb}</math></div> For each of the densities in Exercise [[exercise:0e78fd06fb |Exercise]] calculate  
the first and second moments, <math>\mu_1</math> and <math>\mu_2</math>, directly from their definition and  
verify that <math>g(0) = 1</math>, <math>g'(0) = \mu_1</math>, and <math>g''(0) = \mu_2</math>.
verify that <math>g(0) = 1</math>, <math>g'(0) = \mu_1</math>, and <math>g''(0) = \mu_2</math>.

Latest revision as of 00:07, 15 June 2024

For each of the densities in Exercise calculate the first and second moments, [math]\mu_1[/math] and [math]\mu_2[/math], directly from their definition and verify that [math]g(0) = 1[/math], [math]g'(0) = \mu_1[/math], and [math]g''(0) = \mu_2[/math].