exercise:A98f27f344: Difference between revisions

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(Created page with "<div class="d-none"><math> \newcommand{\NA}{{\rm NA}} \newcommand{\mat}[1]{{\bf#1}} \newcommand{\exref}[1]{\ref{##1}} \newcommand{\secstoprocess}{\all} \newcommand{\NA}{{\rm NA}} \newcommand{\mathds}{\mathbb}</math></div> In Example, assume that we start with a hybrid bred to a hybrid. Find <math> \mat {u}^{(1)},</math> <math> \mat {u}^{(2)},</math> and <math> \mat {u}^{(3)}.</math> What would <math> \mat {u}^{(n)}</math> be?")
 
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\newcommand{\secstoprocess}{\all}
\newcommand{\secstoprocess}{\all}
\newcommand{\NA}{{\rm NA}}
\newcommand{\NA}{{\rm NA}}
\newcommand{\mathds}{\mathbb}</math></div> In [[guide:52e01d4de7#exam 11.1.7 |Example]], assume that we start with a
\newcommand{\mathds}{\mathbb}</math></div> In [[guide:52e01d4de7#exam 11.1.7 |Example]], assume that we start with a hybrid bred to a hybrid.  Find <math> \mat {u}^{(1)},</math> <math> \mat {u}^{(2)},</math> and <math> \mat
hybrid  
bred to a hybrid.  Find <math> \mat {u}^{(1)},</math> <math> \mat {u}^{(2)},</math> and <math> \mat
{u}^{(3)}.</math>   
{u}^{(3)}.</math>   
What would <math> \mat {u}^{(n)}</math> be?
What would <math> \mat {u}^{(n)}</math> be?

Latest revision as of 01:17, 15 June 2024

[math] \newcommand{\NA}{{\rm NA}} \newcommand{\mat}[1]{{\bf#1}} \newcommand{\exref}[1]{\ref{##1}} \newcommand{\secstoprocess}{\all} \newcommand{\NA}{{\rm NA}} \newcommand{\mathds}{\mathbb}[/math]

In Example, assume that we start with a hybrid bred to a hybrid. Find [math] \mat {u}^{(1)},[/math] [math] \mat {u}^{(2)},[/math] and [math] \mat {u}^{(3)}.[/math]

What would [math] \mat {u}^{(n)}[/math] be?