excans:88786ae9bd: Difference between revisions
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(Created page with "'''Solution: C''' By the central limit theorem, June's score is approximately normally distributed with mean 48*3/4 = 36 and variance 48 * 3/4 * 1/4 = 9. Therefore the probability that June passes the exam is approximately equal to the probability that a standard normal variable exceeds (30-36)/3 = -2. This is approximately equal to 0.9773.") |
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'''Solution: | '''Solution: E''' | ||
By the central limit theorem, June's score is approximately normally distributed with mean 48*3/4 = 36 and variance 48 * 3/4 * 1/4 = 9. Therefore the probability that June passes the exam is approximately equal to the probability that a standard normal variable exceeds (30-36)/3 = -2. This is approximately equal to 0.9773. | By the central limit theorem, June's score is approximately normally distributed with mean 48*3/4 = 36 and variance 48 * 3/4 * 1/4 = 9. Therefore the probability that June passes the exam is approximately equal to the probability that a standard normal variable exceeds (30-36)/3 = -2. This is approximately equal to 0.9773. | ||
Latest revision as of 01:43, 27 June 2024
Solution: E
By the central limit theorem, June's score is approximately normally distributed with mean 48*3/4 = 36 and variance 48 * 3/4 * 1/4 = 9. Therefore the probability that June passes the exam is approximately equal to the probability that a standard normal variable exceeds (30-36)/3 = -2. This is approximately equal to 0.9773.