exercise:364ea42c79: Difference between revisions
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(Created page with "<div class="d-none"><math> \newcommand{\ex}[1]{\item } \newcommand{\sx}{\item} \newcommand{\x}{\sx} \newcommand{\sxlab}[1]{} \newcommand{\xlab}{\sxlab} \newcommand{\prov}[1] {\quad #1} \newcommand{\provx}[1] {\quad \mbox{#1}} \newcommand{\intext}[1]{\quad \mbox{#1} \quad} \newcommand{\R}{\mathrm{\bf R}} \newcommand{\Q}{\mathrm{\bf Q}} \newcommand{\Z}{\mathrm{\bf Z}} \newcommand{\C}{\mathrm{\bf C}} \newcommand{\dt}{\textbf} \newcommand{\goesto}{\rightarrow}...") |
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\newcommand{\mathds}{\mathbb} | \newcommand{\mathds}{\mathbb} | ||
</math></div> | </math></div> | ||
<ul style{{=}}"list-style-type:lower-alpha" | <ul style{{=}}"list-style-type:lower-alpha"> | ||
<li> | <li>Show that the graph of <math>(x-3)(y+2) = 10</math> is an | ||
Show that the graph of <math>(x-3)(y+2) = 10</math> is an | |||
equilateral hyperbola with center at | equilateral hyperbola with center at | ||
<math>(3,-2)</math> and asymptotes <math>x=3</math> and <math>y=-2</math>.</li> | <math>(3,-2)</math> and asymptotes <math>x=3</math> and <math>y=-2</math>.</li> | ||
<li>Sketch the graph described in | <li>Sketch the graph described in (a).</li> | ||
</ul> | </ul> | ||
Latest revision as of 01:52, 23 November 2024
[math]
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[/math]
- Show that the graph of [math](x-3)(y+2) = 10[/math] is an equilateral hyperbola with center at [math](3,-2)[/math] and asymptotes [math]x=3[/math] and [math]y=-2[/math].
- Sketch the graph described in (a).