exercise:83665fb974: Difference between revisions
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Compute the terminal point of each of the following | Compute the terminal point of each of the following | ||
vectors, and draw each one as an arrow in the | vectors, and draw each one as an arrow in the | ||
<math>xy</math>-plane. The vectors <math>\vec u</math> and <math>\vec v</math> | <math>xy</math>-plane. The vectors <math>\vec u</math> and <math>\vec v</math> in parts (b), (c), (d), and (e) are defined | ||
in parts | as in part (a). | ||
as in part | <ul style{{=}}"list-style-type:lower-alpha"> | ||
<ul style{{=}}"list-style-type:lower-alpha" | <li> | ||
<li> | |||
<math>\vec u = (3,-2)_P</math> and <math>\vec v = (1,1)_P</math></li> | <math>\vec u = (3,-2)_P</math> and <math>\vec v = (1,1)_P</math></li> | ||
<li> | <li> | ||
<math>\vec u + \vec v</math></li> | <math>\vec u + \vec v</math></li> | ||
<li> | <li> | ||
<math>\vec u - \vec v</math></li> | <math>\vec u - \vec v</math></li> | ||
<li> | <li> | ||
<math>3\vec v</math></li> | <math>3\vec v</math></li> | ||
<li> | <li> | ||
<math>\vec u + 3\vec v</math>.</li> | <math>\vec u + 3\vec v</math>.</li> | ||
</ul> | </ul> | ||
Latest revision as of 22:47, 25 November 2024
[math]
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\newcommand{\sech}{\mathrm{sech\:}}
\newcommand{\csch}{\mathrm{csch\:}}
\newcommand{\conj}[1]{\overline{#1}}
\newcommand{\mathds}{\mathbb}
[/math]
Let [math]P = (2,1)[/math]. Compute the terminal point of each of the following vectors, and draw each one as an arrow in the [math]xy[/math]-plane. The vectors [math]\vec u[/math] and [math]\vec v[/math] in parts (b), (c), (d), and (e) are defined as in part (a).
- [math]\vec u = (3,-2)_P[/math] and [math]\vec v = (1,1)_P[/math]
- [math]\vec u + \vec v[/math]
- [math]\vec u - \vec v[/math]
- [math]3\vec v[/math]
- [math]\vec u + 3\vec v[/math].