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(Created page with "Interest rate is i per annum. Begin with $100 in a bank account. The money accumulates for two years and then $50 is withdrawn. How many more years are needed for the amount in the account to accumulate to $200? (The answer should be a function of i.) '''References''' {{cite web |url=https://web2.uwindsor.ca/math/hlynka/392oldtests.html |last=Hlynka |first=Myron |website=web2.uwindsor.ca | title = University of Windsor Old Tests 62-392 Theory of Interest | access-date=...")
 
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Interest rate is i per annum. Begin with $100 in a bank account. The money accumulates for two years and then $50 is withdrawn. How many more years are needed for the amount
Interest rate is i per annum. Begin with $100 in a bank account. The money accumulates for two years and then $50 is withdrawn. How many more years are needed for the amount in the account to accumulate to $200? (The answer should be a function of i.)
in the account to accumulate to $200? (The answer should be a function of i.)
 
<ul class="mw-excansopts">
<li><math display = "block"> \frac{\log(2)}{\log(1+i)} -1.5</math></li>
<li><math display = "block">\frac{\ln (200)-\ln \left(100(1+i)^2-50\right)}{\ln (1+i)} </math></li>
<li><math display = "block">\frac{\ln (150)-\ln \left(100(1+i)^2\right)}{\ln (1+i)}</math></li>
<li><math display = "block">(\frac{200}{50 + 200i}-1)/i</math></li>
<li><math display = "block">\frac{\ln(2)}{1+i}-2</math></li>
</ul>
 


'''References'''
'''References'''


{{cite web |url=https://web2.uwindsor.ca/math/hlynka/392oldtests.html |last=Hlynka |first=Myron |website=web2.uwindsor.ca | title = University of Windsor Old Tests 62-392 Theory of Interest | access-date=November 23, 2023}}
{{cite web |url=https://web2.uwindsor.ca/math/hlynka/392oldtests.html |last=Hlynka |first=Myron |website=web2.uwindsor.ca | title = University of Windsor Old Tests 62-392 Theory of Interest | access-date=November 23, 2023}}

Latest revision as of 13:17, 26 November 2023

Interest rate is i per annum. Begin with $100 in a bank account. The money accumulates for two years and then $50 is withdrawn. How many more years are needed for the amount in the account to accumulate to $200? (The answer should be a function of i.)

  • [[math]] \frac{\log(2)}{\log(1+i)} -1.5[[/math]]
  • [[math]]\frac{\ln (200)-\ln \left(100(1+i)^2-50\right)}{\ln (1+i)} [[/math]]
  • [[math]]\frac{\ln (150)-\ln \left(100(1+i)^2\right)}{\ln (1+i)}[[/math]]
  • [[math]](\frac{200}{50 + 200i}-1)/i[[/math]]
  • [[math]]\frac{\ln(2)}{1+i}-2[[/math]]


References

Hlynka, Myron. "University of Windsor Old Tests 62-392 Theory of Interest". web2.uwindsor.ca. Retrieved November 23, 2023.