exercise:452120ca41: Difference between revisions
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(Created page with "For a mortality table with a select period of two years, you are given: {| class="table" ! <math>x</math> !! <math>q_{[x]}</math> !! <math>q_{[x]+1}</math> !! <math>q_{x+2}</math> !! <math>x+2</math> |- | 50 || 0.0050 || 0.0063 || 0.0080 || 52 |- | 51 || 0.0060 || 0.0073 || 0.0090 || 53 |- | 52 || 0.0070 || 0.0083 || 0.0100 || 54 |- | 53 || 0.0080 || 0.0093 || 0.0110 || 55 |} The force of mortality is constant between integral ages. Calculate <math>1000_{2.5} q_{[50]...") |
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<ul class="mw-excansopts"><li> 15.2</li><li> 16.4</li><li> 17.7</li><li> 19.0</li><li> 20.2</li></ul> | <ul class="mw-excansopts"><li> 15.2</li><li> 16.4</li><li> 17.7</li><li> 19.0</li><li> 20.2</li></ul> | ||
{{soacopyright|2024}} | |||
Latest revision as of 01:34, 18 January 2024
For a mortality table with a select period of two years, you are given:
| [math]x[/math] | [math]q_{[x]}[/math] | [math]q_{[x]+1}[/math] | [math]q_{x+2}[/math] | [math]x+2[/math] |
|---|---|---|---|---|
| 50 | 0.0050 | 0.0063 | 0.0080 | 52 |
| 51 | 0.0060 | 0.0073 | 0.0090 | 53 |
| 52 | 0.0070 | 0.0083 | 0.0100 | 54 |
| 53 | 0.0080 | 0.0093 | 0.0110 | 55 |
The force of mortality is constant between integral ages.
Calculate [math]1000_{2.5} q_{[50]+0.4}[/math].
- 15.2
- 16.4
- 17.7
- 19.0
- 20.2
Copyright 2024. The Society of Actuaries, Schaumburg, Illinois. Reproduced with permission.