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(Created page with "'''Answer: B''' <math>{ }_{2.5} q_{50}={ }_{2} q_{50}+{ }_{2} p_{50}{ }_{0.5} q_{52}=0.02+(0.98)\left(\frac{0.5}{2}\right)(0.04)=0.0298</math>")
 
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<math>{ }_{2.5} q_{50}={ }_{2} q_{50}+{ }_{2} p_{50}{ }_{0.5} q_{52}=0.02+(0.98)\left(\frac{0.5}{2}\right)(0.04)=0.0298</math>
<math>{ }_{2.5} q_{50}={ }_{2} q_{50}+{ }_{2} p_{50}{ }_{0.5} q_{52}=0.02+(0.98)\left(\frac{0.5}{2}\right)(0.04)=0.0298</math>
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Revision as of 02:33, 18 January 2024

Answer: B

[math]{ }_{2.5} q_{50}={ }_{2} q_{50}+{ }_{2} p_{50}{ }_{0.5} q_{52}=0.02+(0.98)\left(\frac{0.5}{2}\right)(0.04)=0.0298[/math]

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